Reazioni redox in forma molecolare difficili - 4

TA KIMIKA - esercizi risolti
	Esercizi
	Reazioni redox in forma molecolare difficili
	Teoria - 1 - 2 - 3 - 4 - 5 - 6 - 7 - 8 - 9 - 10
	Soluzione con metodo differente: semireazione \| ione-elettrone

Bilanciare la seguente reazione redox: C₄S₂N₄ + K₂MnO₄ + H₂O => CO₂ + MnO₂ + KNO₃ + K₂SO₄ + KOH.
Fonte: http://www.webalice.it/fiorema/Notizie/5A_Liceo_S_T_/REAZIONI_REDOX_IMPEGNATIVE.pdf

Punto 1 - Determinare il numero di ossidazione degli atomi presenti
+4 -2 -3 +1 +6 -2 +1 -2 +4 -2 +4 -2 +1+5-2 +1 +6-2 +1-2+1 C₄S₂N₄ + K₂MnO₄ + H₂O => CO₂ + MnO₂ + KNO₃ + K₂SO₄ + KOH

Punto 2 - Collegare gli atomi con variazione di n.o. con delle frecce
+4 -2 -3 +1 +6 -2 +1 -2 +4 -2 +4 -2 +1+5-2 +1 +6-2 +1-2+1 C₄S₂N₄ + K₂MnO₄ + H₂O => CO₂ + MnO₂ + KNO₃ + K₂SO₄ + KOH \| \| \|_______________________________________\| \| \| \| \| \| \| \| \|________________________________________________________________________\| \| \|___________________________________________________________________________________________\|

Punto 2 - Collegare gli atomi con variazione di n.o. con delle frecce

  +4 -2 -3           +1  +6 -2        +1 -2       +4 -2          +4 -2         +1+5-2         +1 +6-2       +1-2+1 
 C₄S₂N₄ +   K₂MnO₄ + H₂O => CO₂ +   MnO₂ +  KNO₃ +  K₂SO₄ + KOH
      |  |                |_______________________________________|               |               |
      |  |                                                                        |               |
      |  |________________________________________________________________________|               |
      |___________________________________________________________________________________________|

Punto 3 - Bilanciare gli atomi collegati dalle frecce
+4 -2 -3 +1 +6 -2 +1 -2 +4 -2 +4 -2 +1+5-2 +1 +6-2 +1-2+1 C₄S₂N₄ + K₂MnO₄ + H₂O => CO₂ + MnO₂ + 4KNO₃ + 2K₂SO₄ + KOH \| \| \|_______________________________________\| \| \| \| \| \| \| \| \|________________________________________________________________________\| \| \|___________________________________________________________________________________________\|

Punto 3 - Bilanciare gli atomi collegati dalle frecce

  +4 -2 -3           +1  +6 -2        +1 -2       +4 -2          +4 -2         +1+5-2         +1 +6-2       +1-2+1 
 C₄S₂N₄ +   K₂MnO₄ + H₂O => CO₂ +   MnO₂ + 4KNO₃ + 2K₂SO₄ + KOH
      |  |                |_______________________________________|               |               |
      |  |                                                                        |               |
      |  |________________________________________________________________________|               |
      |___________________________________________________________________________________________|

Punto 4 - Esprimere con e^- sulle frecce le 2 variazioni complessive di n.o.
+4 -2 -3 +1 +6 -2 +1 -2 +4 -2 +4 -2 +1+5-2 +1 +6-2 +1-2+1 C₄S₂N₄ + K₂MnO₄ + H₂O => CO₂ + MnO₂ + 4KNO₃ + 2K₂SO₄ + KOH \| \| \|_____2e________________________________\| \| \| \| \| \| \| \| \|_____________________32e________________________________________________\| tot=48e \| \|________________________16e________________________________________________________________\|

Punto 4 - Esprimere con e^- sulle frecce le 2 variazioni complessive di n.o.

  +4 -2 -3           +1  +6 -2        +1 -2       +4 -2          +4 -2         +1+5-2         +1 +6-2       +1-2+1 
 C₄S₂N₄ +   K₂MnO₄ + H₂O => CO₂ +   MnO₂ + 4KNO₃ + 2K₂SO₄ + KOH
      |  |                |_____2e________________________________|               |               |
      |  |                                                                        |               |
      |  |_____________________32e________________________________________________|  tot=48e      |
      |________________________16e________________________________________________________________|

Punto 5 - Bilanciare gli elettroni ed eseguire i prodotti
+4 -2 -3 +1 +6 -2 +1 -2 +4 -2 +4 -2 +1+5-2 +1 +6-2 +1-2+1 C₄S₂N₄ + K₂MnO₄ + H₂O => CO₂ + MnO₂ + 4KNO₃ + 2K₂SO₄ + KOH \| \| \|_____2ex24=48e_________________________\| \| \| \| \| \| \| \| \|_____________________32ex1=32e__________________________________________\| tot=48e \| \|________________________16ex1=16e__________________________________________________________\|
+4 -2 -3 +1 +6 -2 +1 -2 +4 -2 +4 -2 +1+5-2 +1 +6-2 +1-2+1 C₄S₂N₄ + 24K₂MnO₄ + H₂O => CO₂ + 24MnO₂ + 4KNO₃ + 2K₂SO₄ + KOH \| \| \|_____2ex24=48e_________________________\| \| \| \| \| \| \| \| \|_____________________32ex1=32e__________________________________________\| tot=48e \| \|________________________16ex1=16e__________________________________________________________\|

Punto 5 - Bilanciare gli elettroni ed eseguire i prodotti

  +4 -2 -3           +1  +6 -2        +1 -2       +4 -2          +4 -2         +1+5-2         +1 +6-2       +1-2+1 
 C₄S₂N₄ +   K₂MnO₄ + H₂O => CO₂ +   MnO₂ + 4KNO₃ + 2K₂SO₄ + KOH
      |  |                |_____2ex24=48e_________________________|               |               |
      |  |                                                                        |               |
      |  |_____________________32ex1=32e__________________________________________|  tot=48e      |
      |________________________16ex1=16e__________________________________________________________|

  +4 -2 -3           +1  +6 -2        +1 -2       +4 -2          +4 -2         +1+5-2         +1 +6-2       +1-2+1 
 C₄S₂N₄ + 24K₂MnO₄ + H₂O => CO₂ + 24MnO₂ + 4KNO₃ + 2K₂SO₄ + KOH
      |  |                |_____2ex24=48e_________________________|               |               |
      |  |                                                                        |               |
      |  |_____________________32ex1=32e__________________________________________|  tot=48e      |
      |________________________16ex1=16e__________________________________________________________|

Punto 6 - Bilanciare la massa
C₄S₂N₄ + 24K₂MnO₄ + H₂O => 4CO₂ + 24MnO₂ + 4KNO₃ + 2K₂SO₄ + KOH Bilanciamento C
C₄S₂N₄ + 24K₂MnO₄ + H₂O => 4CO₂ + 24MnO₂ + 4KNO₃ + 2K₂SO₄ + 40KOH Bilanciamento K
C₄S₂N₄ + 24K₂MnO₄ + 20H₂O => 4CO₂ + 24MnO₂ + 4KNO₃ + 2K₂SO₄ + 40KOH Bilanciamento H e O
C₄S₂N₄ + 24K₂MnO₄ + 20H₂O => 4CO₂ + 24MnO₂ + 4KNO₃ + 2K₂SO₄ + 40KOH